I attempted to multiply them together, failed teh books answer. So let’s give that a try: If one now consults the On-Line Encyclopedia of Integer Sequences , one can find an explicit, real, non-recursive expression for former sequence, namely:. And what does this expression come out to? My best guess is that the question only asks for the first few terms of the expansion. I’m doing the latter part of a MSc in applied physics, so this is rather basic for me. Scott k 38

Remember that when you take the product of two sums, you have to distribute. My best guess is that the question only asks for the first few terms of the expansion. Scott k 38 This is just testing your understanding of what series are and their relation to regular functions. I am not sure what this represents but it is what my book does for a similar problem later on in the book. Are you sure you want to delete this answer?

Chat or rant, adult content, spam, insulting other members, show more. A much simpler way of doing this is to take the Maclaurin series given in a table tayloor to multiply them out. Taylor series expansion for large fluctuations?

Finding the series expansion for: Well, to sum up, I just liked reading your answer, and I thought I’d share that with you.

I am not sure what this represents but it is what my book does for a similar problem later on in sfries book. I haven’t tripple-checked it Francisco Javier GIl Vidal.

What products of one term of.

Harm to minors, violence or threats, harassment or privacy invasion, impersonation or misrepresentation, fraud or phishing, taglor more. Sign up or log in Sign up using Google. Mathematics Stack Exchange works best with JavaScript enabled. Related Questions Taylor Series Expansion!?

It’s not so obvious, but I will point you to the following result: And other matrix exponentials and, of course, the operator manipulations in Quantum Mechanics Work out what that sequence srries like.

One can now identify the pattern: If one now consults the On-Line Encyclopedia of Integer Sequencesone can find an explicit, real, non-recursive expression for former sequence, namely: Sign up using Facebook. How to do taylor series expansion of arctan x and xsinx? Would they expect you to figure this out?

### How do you find the maclaurin series expansion of f(x)= x sinx? | Socratic

Use the Cauchy product of the series Second method: If one now consults the On-Line Encyclopedia of Integer Sequencesone can find an explicit, real, non-recursive expression for former sequence, namely:. Paul the Pirate Paul the Pirate 2 15 Thus, the only partial products that contribute to the first four terms of the product are ones found in the polynomial product.

And what does this expression come out to? I really think math can be beautiful!

I attempted to multiply them together, failed teh books answer. The easy one here is: Remember that when you take the product of two sums, you have to distribute. Why doesn’t that work for the product? This is just testing your understanding of what series are and their relation to regular functions.

Without this critical step the proof is invalid because the summation of a series involves a limit process, and it is not true in general that “the integral of the limit is the limit of the integrals”. Here is a reference: Now it is true that a Taylor series converges absolutely in the open interval disc of convergence, and uniformly in any CLOSED interval disc strictly contained in the OPEN interval disc of convergence. Post as a guest Name. Why your attempt didn’t work is impossible for us to know without seeing how you attempted to multiply them.

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### How do you find the Maclaurin Series for f(x)= x sinx? | Socratic

Scott k 38 Omnomnomnom Omnomnomnom k 7 91 Are you sure you want to delete this answer? By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service.

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## How do you find the Maclaurin Series for # f(x)= x sinx#?

I tried inputting values for them and then multiplying and that fails as well. The series can be seen to converge even at hte ends of the interval, and continuity considerations allow us to put: This is a fundamental theorem which should be constantly in mind when performing term-by-term integration.

My best guess is that the question only asks for the first few terms of the expansion. By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policyand that your continued use of the website is subject to tayloor policies. So let’s give that a try: Sign up using Email and Password.

Thomas Andrews Thomas Andrews k 12 Now this is a new series whose convergence can be studied afresh, to obtain a convergence radius 1. Ian Mateus Ian Mateus 4, 3 25